28 May, 2023

How Many Questions Of 1Z0-071 Exam Prep

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Total 187 questions Full Exam Access

Question 1

Examine the structure of the CUSTOMERS table: (Choose two.)
1Z0-071 dumps exhibit

CUSTNO is the PRIMARY KEY.
You must determine if any customers' details have been entered more than once using a different CUSTNO, by listing all duplicate names.
Which two methods can you use to get the required result?

Subquery

Self-join

Full outer-join with self-join

Left outer-join with self-join

Right outer-join with self-join

Question 2

View the Exhibit and examine the structure of ORDERS and CUSTOMERS tables. (Choose the best answer.)
1Z0-071 dumps exhibit

You executed this UPDATE statement: UPDATE
( SELECT order_date, order_total, customer_id FROM orders) Set order_date = '22-mar-2007'
WHERE customer_id IN
(SELECT customer_id FROM customers
WHERE cust_last_name = 'Roberts' AND credit_limit = 600); Which statement is true regarding the execution?

It would not execute because a subquery cannot be used in the WHERE clause of an UPDATE statement.

It would not execute because two tables cannot be referenced in a single UPDATE statement.

It would execute and restrict modifications to the columns specified in the SELECT statement.

It would not execute because a SELECT statement cannot be used in place of a table name.

Question 3

View the Exhibit and examine the description of the ORDERS table. (Choose two.)
1Z0-071 dumps exhibit

Which two WHERE clause conditions demonstrate the correct usage of conversion functions?

WHERE Order_date_IN ( TO_DATE('OCT 21 2003', 'MON DD YYYY'), TO_CHAR('NOV 21 2003', 'MON DD YYYY') )

WHERE Order_date > TO_CHAR(ADD_MONTHS(SYSDATE, 6), 'MON DD YYYY')

WHERE TO_CHAR(Order_date, 'MON DD YYYY') = 'JAN 20 2003'

WHERE Order_date > ( TO_DATE('JUL 10 2006', 'MON DD YYYY')

Question 4

On your Oracle 12c database, you invoked SQL *Loader to load data into the EMPLOYEES table in the HR schema by issuing the following command:
$> sqlldr hr/hr@pdb table=employees
Which two statements are true regarding the command?

It succeeds with default settings if the EMPLOYEES table belonging to HR is already defined in the database.

It fails because no SQL *Loader data file location is specified.

It fails if the HR user does not have the CREATE ANY DIRECTORY privilege.

It fails because no SQL *Loader control file location is specified.

Question 5

Evaluate the following ALTER TABLE statement:
ALTER TABLE orders
SET UNUSED (order_date); Which statement is true?

After executing the ALTER TABLE command, you can add a new column called ORDER_DATE to the ORDERS table.

The ORDER_DATE column should be empty for the ALTER TABLE command to execute succsessfully.

ROLLBACK can be used to get back the ORDER_DATE column in the ORDERS table.

The DESCRIBE command would still display the ORDER_DATE column.

Question 6

Examine the structure of the MEMBERS table: (Choose the best answer.)
1Z0-071 dumps exhibit

Examine the SQL statement:
SQL > SELECT city, last_name LNAME FROM MEMBERS ORDER BY 1, LNAME DESC;
What would be the result execution?

It displays all cities in descending order, within which the last names are further sorted in descending order.

It fails because a column alias cannot be used in the ORDER BY clause.

It fails because a column number and a column alias cannot be used together in the ORDER BY clause.

It displays all cities in ascending order, within which the last names are further sorted in descending order.

Question 7

Which three tasks can be performed using SQL functions built into Oracle Database?

displaying a date in a nondefault format

finding the number of characters in an expression

substituting a character string in a text expression with a specified string

combining more than two columns or expressions into a single column in the output

Question 8

View the exhibit and examine the data in the PROJ_TASK_DETAILS table. (Choose the best answer.)
1Z0-071 dumps exhibit

The PROJ_TASK_DETAILS table stores information about project tasks and the relation between them. The BASED_ON column indicates dependencies between tasks.
Some tasks do not depend on the completion of other tasks.
You must generate a report listing all task IDs, the task ID of any task upon which it depends and the name of the employee in charge of the task upon which it depends.
Which query would give the required result?

SELECT p.task_id, p.based_on, d.task_in_chargeFROM proj_task_details p JOIN proj_task_details dON (p.task_id = d.task_id);

SELECT p.task_id, p.based_on, d.task_in_chargeFROM proj_task_details p FULL OUTER JOIN proj_task_details dON (p.based_on = d.task_id);

SELECT p.task_id, p.based_on, d.task_in_chargeFROM proj_task_details p JOIN proj_task_details dON (p.based_on = d.task_id);

SELECT p.task_id, p.based_on, d.task_in_chargeFROM proj_task_details p LEFT OUTER JOIN proj_task_details dON (p.based_on = d.task_id);

Question 9

View the Exhibit and examine the structures of the employees and departments tables.
1Z0-071 dumps exhibit

You must update the employees table according to these requirements::
-Update only those employees who work in Boston or Seattle (locations 2900 and 2700).
-Set department_id for these employees to the department id corresponding to London (locationid 2100).
-Set the employees' salary in iocation_id 2100 to 1.1 times the average salary of their department.
-Set the employees' commission In location_id 2100 to 1.5 times the average commission of their department. You issue this command:
1Z0-071 dumps exhibit

What is the result?

It executes successfully but does not produce the desired update.

It executes successfully and produces the desired update.

It generates an error because multiple columns cannot be specified together in an UPDATE statement.

It generates an error because a subquery cannot have a join condition in an update statement.

Question 10

Examine the create table statements for the stores and sales tables.
SQL> CREATE TABLE stores(store_id NUMBER(4) CONSTRAINT store_id_pk PRIMARY KEY, store_name VARCHAR2(12), store_address VARCHAR2(20), start_date DATE);
SQL> CREATE TABLE sales(sales_id NUMBER(4) CONSTRAINT sales_id_pk PRIMARY KEY, item_id NUMBER(4), quantity NUMBER(10), sales_date DATE, store_id NUMBER(4), CONSTRAINT store_id_fk FOREIGN KEY(store_id) REFERENCES stores(store_id));
You executed the following statement: SQL> DELETE from stores
WHERE store_id=900;
The statement fails due to the integrity constraint error:
ORA-02292: integrity constraint (HR.STORE_ID_FK) violated
Which three options ensure that the statement will execute successfully?

Disable the primary key in the STORES table.

Use CASCADE keyword with DELETE statement.

DELETE the rows with STORE_ID = 900 from the SALES table and then delete rows from STORES table.

Disable the FOREIGN KEY in SALES table and then delete the rows.

Create the foreign key in the SALES table on SALES_ID column with on DELETE CASCADE option.

Question 11

Examine the structure of the BOOKS_ TRANSACTIONS table:
1Z0-071 dumps exhibit

Examine the SQL statement:
1Z0-071 dumps exhibit

Which statement is true about the outcome?

It displays details only for members who have borrowed before today with RM as TRANSACTION_TYPE.

It displays details for members who have borrowed before today's date with either RM asTRANSACTION_TYPE or MEMBER_ID as A101 and A102.

It displays details for only members A101and A102 who have borrowed before today with RM as TRANSACTION_TYPE.

It displays details for members who have borrowed before today with RM as TRANSACTION_TYPE and the details for members A101 or A102.

Question 12

Examine the structure of the ORDERS table: (Choose the best answer.)
1Z0-071 dumps exhibit

You want to find the total value of all the orders for each year and issue this command:
SQL> SELECT TO_CHAR(order_date,'rr'), SUM(order_total) FROM orders GROUP BY TO_CHAR(order_date, 'yyyy');
Which statement is true regarding the result?

It executes successfully but does not give the correct output.

It executes successfully but gives the correct output.

It returns an error because the TO_CHAR function is not valid.

It return an error because the datatype conversion in the SELECT list does not match the data type conversion in the GROUP BY clause.

Question 13

You need to produce a report where each customer’s credit limit has been incremented by $1000. In the output, the customer’s last name should have the heading Name and the incremented credit limit should be labeled New Credit Limit. The column headings should have only the first letter of each word in uppercase.
Which statement would accomplish this requirement?

SELECT cust_last_name AS “Name”, cust_credit_limit + 1000AS “New Credit Limit”FROM customers;

SELECT cust_last_name AS Name, cust_credit_limit + 1000AS New Credit LimitFROM customers;

SELECT cust_last_name AS Name, cust_credit_limit + 1000“New Credit Limit”FROM customers;

SELECT INITCAP (cust_last_name) “Name”, cust_credit_limit + 1000INITCAP (“NEW CREDIT LIMIT”)FROM customers;

Question 14

Examine the structure of the EMPLOYEES table. (Choose the best answer.)
1Z0-071 dumps exhibit

You must display the details of employees who have manager with MANAGER_ID 100, who were hired in the past 6 months and who have salaries greater than 10000.

SELECT last_name, hire_date, salaryFROM employeesWHERE salary > 10000UNION ALL SELECT last_name, hire_date, salaryFROM employeesWHERE manager_ID = (SELECT employee_id FROM employees WHERE employee_id = 100)INETRSECTSELECT last_name, hire_date, salaryFROM employees WHERE hire_date > SYSDATE- 180;

SELECT last_name, hire_date, salaryFROM employeesWHERE manager_id = (SELECT employee_id FROM employees WHERE employee_id = 100)UNION ALL(SELECT last_name, hire_date, salaryFROM employeesWHERE hire_date > SYSDATE -180INTERSECTSELECT last_name, hire_date, salaryFROM employeesWHERE salary > 10000);

SELECT last_name, hire_date, salaryFROM employeesWHERE manager_id = (SELECT employee_id FROM employees WHERE employee_id = '100')UNIONSELECT last_name, hire_date, salaryFROM employeesWHERE hire_date > SYSDATE -180INTERSECTSELECT last_name, hire_date, salaryFROM employeesWHERE salary > 10000;

(SELECT last_name, hire_date, salaryFROM employeesWHERE salary > 10000UNION ALLSELECT last_name, hire_date, salaryFROM employeesWHERE manager_ID = (SELECT employee_id FROM employees WHERE employee_id = 100))UNIONSELECT last_name, hire_date, salaryFROM employeesWHERE hire_date > SYSDATE -180;

Question 15

View the Exhibit and examine the structure of the SALES and PRODUCTS tables. (Choose two.)
1Z0-071 dumps exhibit

In the SALES table, PROD_ID is the foreign key referencing PROD_ID in the PRODUCTS table. You must list each product ID and the number of times it has been sold.
Examine this query which is missing a JOIN operator: SQL > SELECT p.prod_id, count(s.prod_id)
FROM products p sales s ON p.prod_id = s.prod_id
GROUP BY p.prod_id;
Which two JOIN operations can be used to obtain the required output?

FULL OUTER JOIN

JOIN

LEFT OUETR JOIN

RIGHT OUTER JOIN

Question 16

Evaluate the following query:
SQL> SELECT TRUNC (ROUND (156.00, -1),-1) FROM DUAL;
What would be the outcome?

150

200

160

100

Question 17

Which task can be performed by using a single Data Manipulation Language (DML) statement?

Removing all data only from a single column on which a primary key constraint is defined.

Removing all data from a single column on which a unique constraint is defined.

Adding a column with a default value while inserting a row into a table.

Adding a column constraint while inserting a row into a table.

Question 18

View the Exhibit and examine the structure of the PROMOTIONS table.
1Z0-071 dumps exhibit

Evaluate the following SQL statement:
1Z0-071 dumps exhibit

Which statement is true regarding the outcome of the above query?

It produces an error because subqueries cannot be used with the CASE expression.

It shows COST_REMARK for all the promos in the promo category ‘TV’.

It shows COST_REMARK for all the promos in the table.

It produces an error because the subquery gives an error.

Question 19

View the Exhibit and examine the structure in the EMPLOYEES tables.
1Z0-071 dumps exhibit

Evaluate the following SQL statement: SELECT employee_id, department_id FROM employees
WHERE department_id= 50 ORDER BY department_id UNION
SELECT employee_id, department_id FROM employees
WHERE department_id=90 UNION
SELECT employee_id, department_id
FROM employees
WHERE department_id=10;
What would be the outcome of the above SQL statement?

The statement would not execute because the positional notation instead of the column name should be used with the ORDER BY clause.

The statement would execute successfully and display all the rows in the ascending order of DEPARTMENT_ID.

The statement would execute successfully but it will ignore the ORDER BY clause and display the rows in random order.

The statement would not execute because the ORDER BY clause should appear only at the end of the SQL statement, that is, in the last SELECT statement.

Question 20

Which statement is true regarding the default behaviour of the ORDER by clause?

Numeric values are displayed in descending order if they have decimal positions.

Only columns that are specified in the SELECT list can be used in the ORDER by clause.

In a character sort, the values are case-sensitive.

NULLs are not including in the sort operation

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Total 187 questions Full Exam Access